Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 542: 33b

Answer

$180.9$ seconds

Work Step by Step

Water's specific heat is $4.186 \frac{kJ}{kg^{\circ}C}$. Therefore it takes, $150*17*4.186 = 10674.3 $ $kJ$ to heat the water up this much. For a $59 $ kW heater, this will take $10674.3/59$ seconds, or $180.9$ seconds.
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