Answer
$4.27\times 10^4J$
Work Step by Step
We know that;
$Q=cm(T_f-T_i)$
We plug in the known values to obtain:
$Q=236(0.13)(1235-288)=2.91\times 10^4J$
We also know that;
$Q=mL_F$
$Q=0.13(105\times 10^3)=1.36\times 10^4$
Thus, the total heat required is
$2.91\times 10^4+1.36\times 10^4=4.27\times 10^4J$
