Answer
$c_m=26.2\frac{J}{mol.K}$
Work Step by Step
We know that;
$c_m=\frac{Q}{N(T_f-T_i)}$
We plug in the known values to obtain:
$c_m=\frac{314}{0.6(45-25)}=26.2\frac{J}{mol.K}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 542: 24b
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