Answer
$109g$
Work Step by Step
We know that;
$m=\frac{Q}{L_F}$
We plug in the known values to obtain:
$m=\frac{50.2}{333}=0.151Kg=151g$
Thus, the amount of water that remains unfrozen is:
$260-151=109g$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 542: 28
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