Answer
$1.09\times10^{6}\;N$
Work Step by Step
The total force compressing the sphere’s surface is
$F=PA$
or, $F=(P_o+\rho gh)A$
or, $F=(P_o+\rho gh)\times4\pi r^2$
Substituting the given values
$F=(1.01\times10^{5}+1025\times9.81\times2.22\times10^3)\times4\times\pi \times(0.0622)^2\;N$
or, $\boxed{F=1.09\times10^{6}\;N}$
