Answer
$1.08\times10^{2}\;m/s$
Work Step by Step
We have already formulated the aircraft’s airspeed using a pitot tube
$v=\frac{2P}{ρ_{air}}$
Substituting the given values
$v=\frac{2\times180}{0.031}\;m/s$
or, $\boxed{v=1.08\times10^{2}\;m/s}$