Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 408: 32d

Answer

The buoyant force is $~~2500~N$ $tension+buoyant~force = weight$

Work Step by Step

In part (a), we found that the downward force on the cube due to pressure is $3.71\times 10^4~N$ In part (b), we found that the upward force on the cube due to pressure is $3.96\times 10^4~N$ The buoyant force is the difference between these two forces: $F_b = 3.96\times 10^4~N-3.71\times 10^4~N$ $F_b = 2500~N$ The buoyant force is $~~2500~N$ Since the cube is in equilibrium, the magnitude of the upward forces is equal to the magnitude of the downward forces. That is: $tension+buoyant~force = weight$
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