Answer
$$120\times 133.32-1.06\times 10^{3}\times \left( 4\times 9.8\right) \times 30\times 10^{-2}\approx 3532.8P_{a}\approx 26.49torr$$
Work Step by Step
$$1torr=133.321Pa\Rightarrow P=P_{0}-\rho a\Delta h\approx 120\times 133.32-1.06\times 10^{3}\times \left( 4\times 9.8\right) \times 30\times 10^{-2}=$$
$$120\times 133.32-1.06\times 10^{3}\times \left( 4\times 9.8\right) \times 30\times 10^{-2}\approx 3532.8P_{a}\approx 26.49torr$$
