Answer
$S=0.0784$ m
Work Step by Step
We know that:
$F=weight-F_b$
According to Archimedes' principle, the buoyant force $F_b=m_fg$ where $m_f$ is the mass of the fluid that has been displaced.
Also, $F=ma$ (according to Newton's second law). So the above equation becomes:
$ma=mg-m_fg$
We plug in the known values to obtain:
$5a=5\times9.8-3\times 9.8$
$a=3.92\frac{m}{s^2}$
Next, we consider $S=v_it+\frac{1}{2}t^2$. However, $v_i=0\frac{m}{s}$. Therefore, the formula becomes:
$S=\frac{1}{2}at^2$
We plug in the known values to obtain:
$S=\frac{1}{2}\times3.92\times(0.200)^2$
$S=0.0784m$
