Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 408: 32c

Answer

The tension in the rope is $~~1910~N$

Work Step by Step

In part (a), we found that the downward force on the cube due to pressure is $3.71\times 10^4~N$ In part (b), we found that the upward force on the cube due to pressure is $3.96\times 10^4~N$ We can find the tension $F_T$ in the rope: $F_T+(3.96\times 10^4~N) = mg+(3.71\times 10^4~N)$ $F_T = (450~kg)(9.8~m/s^2)+(3.71\times 10^4~N)-(3.96\times 10^4~N)$ $F_T = 1910~N$ The tension in the rope is $~~1910~N$
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