Answer
$1.07$ seconds.
Work Step by Step
Since the downward force on the physicist is $220 N$, the magnitude of the gravitational acceleration near the physicist is $3.66 m/s^2$. Using $h = h_0-0.5gt^2$, we get $1.83t^2 = 2.1, t^2 = 1.145, t = 1.07 s$
