Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 383: 65b

Answer

The kinetic energy depends on $~~\frac{1}{r}$

Work Step by Step

We can find an expression for the square of the speed: $\frac{GMm}{r^2} = \frac{mv^2}{r}$ $v^2 = \frac{GM}{r}$ We can find an expression for the kinetic energy: $K = \frac{1}{2}mv^2$ $K = \frac{GMm}{2r}$ The kinetic energy depends on $~~\frac{1}{r}$
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