Answer
Satellite B has a greater total energy than satellite A.
Work Step by Step
Let $R_E$ be the Earth's radius
The total energy of an orbiting satellite at a height $h$ above the Earth's surface is $E = -\frac{GMm}{2(R_E+h)}$
We can see that as the value of $h$ increases, the total energy becomes less negative. (That is, the magnitude decreases as the value moves closer to zero.)
Since satellite B is at a higher altitude than satellite A, satellite B has a greater total energy than satellite A.
