Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 383: 64b

Answer

36 N

Work Step by Step

$F_{1}=\frac{GMm}{r_{1}^{2}}$ $F_{2}=\frac{GMm}{r_{2}^{2}}$ $\frac{F_{2}}{F_{1}}=\frac{\frac{1}{r_{2}^{2}}}{\frac{1}{r_{1}^{2}}}=\frac{r_{1}^{2}}{r_{2}^{2}}$ $\implies F_{2}=\frac{r_{1}^{2}}{r_{2}^{2}}\times F_{1}=(\frac{r_{1}}{r_{2}})^{2}\times F_{1}$ $=(\frac{2.0\times10^{7}\,m}{3.0\times10^{7}\,m})^{2}\times80\,N=(\frac{2.0}{3.0})^{2}\times80\,N=36\,N$
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