Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 383: 68e

Answer

In the new elliptical orbit, the total energy is $$ E=K+U=5.78 \times 10^{10} \mathrm{J}+\left(-1.18 \times 10^{11} \mathrm{J}\right)=-6.02 \times 10^{10} \mathrm{J} $$

Work Step by Step

In the new elliptical orbit, the total energy is $$ E=K+U=5.78 \times 10^{10} \mathrm{J}+\left(-1.18 \times 10^{11} \mathrm{J}\right)=-6.02 \times 10^{10} \mathrm{J} $$
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