Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 287: 9b

Answer

Angle it rotates in coming to rest $ = 18.9$ $ rad$

Work Step by Step

The formula to be used here is: $\omega_{f}^{2} = \omega_{o}^{2} + 2\alpha(\theta-\theta_{o})$ By arranging the equation, we make $(\theta-\theta_{o})$ the subject of formula: $(\theta-\theta_{o}) = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\alpha}$ Substituting the values in formula and solving: $(\theta-\theta_{o}) = \frac{0^{2}-(12.6)^{2}}{2\times (-4.2)}$ $(\theta-\theta_{o})=18.9 $ $rad$
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