Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 287: 4d

Answer

$32\dfrac {rad}{s^{2}}$

Work Step by Step

Angular velocity of object is: $w=\dfrac {\partial \theta }{\partial t}=\dfrac {\partial }{\partial t}\left( 2+4t^{2}+2t^{3}\right) =8t+6t^{2}............\left( 1\right) $ Angular acceleration of the object is: $\alpha =\dfrac {\partial w\left( t\right) }{\partial t}...................\left( 2\right) $ Using (1) and (2) we get, $\alpha =\dfrac {\partial w\left( t\right) }{\partial t}=\dfrac {\partial \left( 8t+6t^{2}\right) }{\partial t}=8+12t$ So, at time $t=2s$, we get: $\alpha \left( 2\right) =8+12\times 2=32\dfrac {rad}{s^{2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.