## Fundamentals of Physics Extended (10th Edition)

$6\dfrac {rad}{s^{2}}$
To find the angular acceleration, we need to find the angular velocity first. So, the angular velocity of point is: $w\left( t\right) =\dfrac {\partial \left( \theta \right) }{\partial t}=\dfrac {\partial }{\partial t}\left( 4t-3t^{2}+t^{3}\right) =4+3t^{2}-6t...................(1)$ The angular acceleration at any given time is: $\alpha \left( t\right) =\dfrac {\partial w}{\partial t}=\dfrac {\partial }{\partial t}\left( 4-6t+3t ^{2}\right)=6t-6 ............................(2)$ So using (2) and $t=2s$, we get: $\alpha \left( 2\right) =6\times 2-6=6\dfrac {rad}{s^{2}}$