## Fundamentals of Physics Extended (10th Edition)

Published by Wiley

# Chapter 10 - Rotation - Problems - Page 287: 3b

#### Answer

$11.9\ rad/s$

#### Work Step by Step

From the kinematic equations, time taken by the toast to fall is: $t=\sqrt \frac{2s}{g}$ $t=\sqrt \frac{2\times 0.76\ m}{9.8\ m/s^2}$ $t=0.394\ s$ For maximum angular speed, the toast rotates at $\frac{3}{4}$ of a revolution. The formula for angular speed is $\omega=\frac{Δθ( rev)}{ΔT(sec)}$ Therefore; $ω_{max}=\frac{0.75\ rev}{0.394\ s}$ Since $1\ rev=2π\ rad$; $ω_{max}=\frac{0.75\times 2\pi }{0.394\ s}=11.9\ rad/s$

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