Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 287: 2b

Answer

$\omega=1.75\times10^{-3}\frac{rad}{s}$

Work Step by Step

The minute hand of a clock completes a round trip in 3600 seconds. Thus, the angular speed of the minute hand is given as $\omega=\frac{2\pi}{3600}=\frac{2(3.1416)}{3600}$ $\omega=1.75\times10^{-3}\frac{rad}{s}$
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