Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 38

Answer

Please see the work below.

Work Step by Step

According to law of conservation of energy $\frac{1}{2}mv^2=mgdsin(\theta)$ This simplifies to: $d=\frac{v^2}{2gsin(\theta)}$ We plug in the known values to obtain: $d=\frac{(\frac{110}{3.6})^2}{(2)(9.8)sin(30)}$ $d=95m$
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