Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 36

Answer

Please see the work below.

Work Step by Step

(a) We know that $U=-\int Fdx$ $U=-\int (\frac{A}{x^2})dx$ $U=\frac{A}{x}$ Thus, the potential energy difference is: $\Delta U=\frac{A}{x_2}-\frac{A}{x_1}$ (b) The potential energy difference is given as $\Delta U=\frac{A}{\infty}-\frac{A}{x_1}=-\frac{A}{x_1}$
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