Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 32

Answer

Please see the work below.

Work Step by Step

We know that $\Delta U=\frac{1}{2}Kx_{\circ}^2$ This can be rearranged as: $K=\frac{2\Delta V}{x_{\circ}^2}$ We plug in the known values to obtain: $K=\frac{2\times 2\times 10^{-21}}{(1.46\times 10^{-12})^2}=1879\frac{N}{m}$
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