Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 40

Answer

Please see the work below.

Work Step by Step

We know that according to law of conservation of energy $(\frac{1}{2})mv^2=mg(L-Lcos(50))$ This simplifies to: $v=\sqrt{2g(L-Lcos(50))}$ We plug in the known values to obtain: $v=\sqrt{(2)(9.8)(3.2-3.2cos(50))}$ $v=4.7\frac{m}{s}$
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