Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 35

Answer

Please see the work below.

Work Step by Step

We know that the force is: $F=-Kx-cx^3$ and the energy is: $W=-\int Fdx$ $\implies W=-\int (-kx-cx^3)dx$ $W=k(\frac{x^2}{2})+c(\frac{x^4}{4})$ We plug in the known values to obtain: $W=(220)(\frac{(0.15)^2}{2})+(3.1)(\frac{(0.15)^4}{4})=2.5J$
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