Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 24

Answer

Please see the work below.

Work Step by Step

We know that $\Delta K=-f_k d$ This can be rearranged as: $d=\frac{\Delta K}{-f_k}$ We plug in the known values to obtain: $d=\frac{\frac{-1}{2}mv^2}{-\mu_k mg}$ $d=\frac{v^2}{2\mu g}$ $d=\frac{8.2}{2\times 0.023\times 9.8}=22.71m$
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