Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems - Page 125: 23


Please see the work below.

Work Step by Step

According to law of conservation of energy $mgh=\frac{1}{2}Kx^2$ This simplifies to: $K=\frac{2mgh}{x^2}$ We plug in the known values to obtain: $K=\frac{(2)(0.065)(9.8)(35)}{(0.14)^2}=2300\frac{N}{m}$
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