Answer
Please see the work below.
Work Step by Step
We can find the potential energy as follows:
$U=\frac{1}{2}Kx^2$
We plug in the known values to obtain:
$U=\frac{1}{2}(320)(0.18)^2$
$U=5.2J$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 7 - Exercises and Problems - Page 125: 16
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