Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 18

Answer

Please see the work below.

Work Step by Step

We know that $U=\frac{1}{2}Kx^2$ We plug in the known values to obtain: $U=\frac{1}{2}(0.046\frac{pN}{\mu m})(26\mu m)^2$ $U=\frac{1}{2}(0.046\times \frac{1\times 10^{-12}N}{1\times 10^{-6}m})(26\times 10^{-6}m)^2$ $U=1.6\times 10^{-17}J$
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