Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 21

Answer

Please see the work below.

Work Step by Step

We know that according to law of conservation of energy $mgh=(\frac{1}{2})Kx^2$ This simplifies to: $h=\frac{Kx^2}{2mg}$ $h=\frac{(430)(0.71)^2}{(2)(0.120)(9.8)}=92m$
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