Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems - Page 86: 22


a) $m = 7.065 kg $ b) $m = 3.947 kg $

Work Step by Step

a) We assume that the pulley is massless. We know that the left mass is 2.1 kg. Thus, we treat this as a system, and we use Newton's second law to find: $-.64(m+2.1)=2.1gsin60-mgsin20\\ m = 7.065 kg $ b) We use a similar process to find: $.76(m+2.1)=2.1gsin60-mgsin20\\ m = 3.947 kg $
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