Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems - Page 86: 15


$ \theta = 22.4 ^{\circ}$

Work Step by Step

For this to happen, we need the force in the downward direction to be $3.7m/s^2$ We know that: $g_{mars}=g_{earth}sin( \theta)$ This gives: $\theta = sin^{-1}( \frac{g_{mars}}{g_{earth}})=sin^{-1}( .378)$ $ \theta = 22.4 ^{\circ}$
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