Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems - Page 86: 19


$ \theta = cos ^{-1} (580/700)=34^{\circ}$

Work Step by Step

They can cross the bridge safely. We know that the force, 700 N, times the cosine of the incline angle of the bridge gives the normal force. Thus, we see: $ F_{max}= Ncos( \theta)$ $ \theta = cos ^{-1} (F_{max}/N)$ This gives: $ \theta = cos ^{-1} (580/700)=34^{\circ}$
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