Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems - Page 86: 16


Please see the work below.

Work Step by Step

We know that $a=gsin(\theta)=9.8sin(24)=3.986\frac{m}{s^2}$ $d=(\frac{1}{2})at^2$ This simplifies to: $t=\sqrt{\frac{2d}{a}}=\sqrt{\frac{(2)(1300)}{3.986}}=26s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.