Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems: 17

Answer

Please see the work below.

Work Step by Step

We know that $F_x=ma$ We plug in the known values to obtain: $F_x=(1400)(0.57)=798N$ Now we can find the tension as $T=\frac{F_x}{cos25}=\frac{798}{cos25}=880N$
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