Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems - Page 350: 51



Work Step by Step

We know that the change in temperature has to do with the masses and the specific heats of the substances. Thus, we find that the final temperature is: $T_f=288+(140)(\frac{2.4}{3.5})(\frac{.87}{4.184})=308K$ Now, we find the total change in entropy: $\Delta S = (3.5)(4184)(ln(\frac{308}{288}))+2.4(.87)(ln(\frac{308}{428}))\approx 160J/K$
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