Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems: 49

Answer

0

Work Step by Step

Since $P_1V_1^{\gamma}=P_2V_2^{\gamma}$, we see that this process is adiabatic. Since this is an adiabatic process consisting only of constant volume and constant pressure segments, it follows that the entropy change is 0.
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