## Essential University Physics: Volume 1 (3rd Edition)

a) Since there are two volumes of equal amounts of the same substance, we know that the final temperature will be the average of the two, which is: $=\frac{353+283}{2}=318 K$ Thus, we find for the warm water: $\Delta S = (.25)(4,184)(ln(\frac{318}{383}))=-194.53$ b) For the cold water: $\Delta S = (.25)(4,184)(ln(\frac{318}{283}))=122$ c) We add these to find the total: $122-194=-72$