Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems - Page 350: 48


a) -194.5 b) 122 c) -72

Work Step by Step

a) Since there are two volumes of equal amounts of the same substance, we know that the final temperature will be the average of the two, which is: $=\frac{353+283}{2}=318 K $ Thus, we find for the warm water: $\Delta S = (.25)(4,184)(ln(\frac{318}{383}))=-194.53$ b) For the cold water: $\Delta S = (.25)(4,184)(ln(\frac{318}{283}))=122$ c) We add these to find the total: $122-194=-72$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.