Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems: 36

Answer

Please see the work below.

Work Step by Step

We know that $COP=\frac{T_c}{T_h-T_c}$ We plug in the known values to obtain: $COP=\frac{273+4}{(273+30)-(273+4)}$ $COP=10.654$ Now we can find the rate of electrical energy as $P=COP\space P_c$ We plug in the known values to obtain: $P=(10.654)(340)$ $P=3600W$
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