Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems - Page 350: 44


$2.3 \times 10^4 J/K$

Work Step by Step

We know that the temperature in degrees Kelvin is 303.15 Kelvin, and, using conversions, we also know that 7100 kJ equals 7,100,000 Joules. Thus, we find: $ \Delta S = \frac{Q}{T}=\frac{7,100,000}{303}=2.3 \times 10^4 J/K$
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