## Essential University Physics: Volume 1 (3rd Edition)

$2.3 \times 10^4 J/K$
We know that the temperature in degrees Kelvin is 303.15 Kelvin, and, using conversions, we also know that 7100 kJ equals 7,100,000 Joules. Thus, we find: $\Delta S = \frac{Q}{T}=\frac{7,100,000}{303}=2.3 \times 10^4 J/K$