Answer
(a) 1 (b) 0.5 (c) 1.3
Work Step by Step
(a)We know that
$\frac{V_1}{V_2}=2$
For diatomic gas
$\gamma=1$
(b) As $\frac{E_{int_2}}{E_{int1}}=\frac{V_2}{V_1}=0.5$
(c) We know that
$T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}$
This can be rearranged as:
$\frac{T_2}{T_1}=(\frac{V_1}{V_2})^{\gamma-1}$
$\implies \frac{E_{int2}}{E_{int1}}=\frac{T_2}{T_1}=2^{1.4-1}=1.3$
