Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems: 32

Answer

Please see the work below.

Work Step by Step

(a) We know that for an isothermal process $Q=-W$ $\implies Q=-(-3.3KJ)=3.3KJ$ (b) We know that $W=-nRTln(\frac{V_2}{V_1})$ We plug in the known values to obtain: $-3300=-n(8.314)(440)ln(\frac{10}{1})$ $n=0.39 \ moles$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.