# Chapter 18 - Exercises and Problems - Page 331: 32

#### Work Step by Step

(a) We know that for an isothermal process $Q=-W$ $\implies Q=-(-3.3KJ)=3.3KJ$ (b) We know that $W=-nRTln(\frac{V_2}{V_1})$ We plug in the known values to obtain: $-3300=-n(8.314)(440)ln(\frac{10}{1})$ $n=0.39 \ moles$

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