Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems - Page 331: 42

Answer

.61 times the original volume.

Work Step by Step

We use the known equation to find: $(\frac{V_2}{V_1})^{\gamma}=\frac{p_1}{p_2}$ $(\frac{V_2}{V_1})^{1.4}=.5$ $(\frac{V_2}{V_1})^{1.4}=.61$
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