Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems: 33

Answer

Please see the work below.

Work Step by Step

We know that $\frac{dQ}{dt}=\frac{dU}{dt}-\frac{dW}{dt}$ We plug in the known values to obtain: $\frac{dQ}{dt}=(500)-(120)$ $\frac{dQ}{dt}=380W$
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