Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems: 43

Answer

Please see the work below.

Work Step by Step

(a) We know that $T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}$ This can be rearranged as: $T_2=T_1(\frac{V_1}{V_2})^{\gamma-1}$ We plug in the known values to obtain: $T_2=320K\times (10.2)^{1.4-1}$ $T_2=810K$ (b) We know that $P_1V_1^{\gamma}=P_2V_2^{\gamma}$ This can be rearranged as: $P_2=P_1(\frac{V_1}{V_2})^{\gamma}$ We plug in the known values to obtain: $P_2=1atm(10.2)^{1.4}$ $P_2=25.8atm$
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