Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Exercises and Problems - Page 300: 54


$.99 \times 10^{-6} s$

Work Step by Step

We use the following equation: $ P = e\sigma A(T^4-T_0^4)$ Thus, converting the temperatures to Kelvin and the energy to Joules, we obtain: $ P = (.95)(5.7\times10^{-8}\times (1))(310^4 - 293^4)= 101 \ W$ Recalling that power is equal to change in energy over change in time, we adjust this equation to find: $ \Delta t = \frac{E}{P}=\frac{100\times10^{-6}}{101}=.99\times 10^{-6}s$
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