## Essential University Physics: Volume 1 (3rd Edition)

$.99 \times 10^{-6} s$
We use the following equation: $P = e\sigma A(T^4-T_0^4)$ Thus, converting the temperatures to Kelvin and the energy to Joules, we obtain: $P = (.95)(5.7\times10^{-8}\times (1))(310^4 - 293^4)= 101 \ W$ Recalling that power is equal to change in energy over change in time, we adjust this equation to find: $\Delta t = \frac{E}{P}=\frac{100\times10^{-6}}{101}=.99\times 10^{-6}s$