## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 16 - Exercises and Problems - Page 300: 46

#### Answer

$$2 Ms$$

#### Work Step by Step

We know that the equation for time is given by: $$t = \frac{Q}{P}$$ We substitute a different equation for Q: $$t= \frac{mc \Delta T}{P}$$ We know that the numerical value for mass is equal to the number of liters of water, so: $$m = \pi r^2 d \times 1000 Kg$$ This gives: $$t= \frac{ \pi r^2 d \times 1000c \Delta T}{P}$$ where d is the depth of the water We plug in the given values to find: $$2 Ms$$

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