# Chapter 16 - Exercises and Problems - Page 300: 50

Stone house: 9 hours Wood house: 3 hours

#### Work Step by Step

We divide the value of Q by the rate at which heat is absorbed to find: $\Delta t = \frac{ \Delta Q}{10^5} = \frac{75 \times 2000 \times .2 \times 30}{10^5 } = 9 \ hours$ For the wood house: $\Delta t = \frac{ \Delta Q}{10^5} = \frac{15 \times 2000 \times .33 \times 30}{10^5 } = 3 \ hours$

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