Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Exercises and Problems: 57

Answer

Please see the work below.

Work Step by Step

We know that $Q_{water}=-Q_{copper}$ $m_{water} c_{water}\Delta T_{water}=-m_{copper}c_{copper}\Delta T_{copper}$ We plug in the known values to obtain: $(1.0)(4184)(25-20)=(m_{copper})(386)(300-25)$ $m_{copper}=0.20Kg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.