## Essential University Physics: Volume 1 (3rd Edition)

For all of the following problems, we use the following equation: $\frac{P_1}{P_2}=\frac{T_1}{T_2}$ Thus, we find: a) $\frac{101}{P_2}=\frac{273}{373} \\ P_2 = 138 \ kPa$ b) $\frac{101}{P_2}=\frac{273}{90.2}\\ P_2 = 33.4 \ kPa$ c) $\frac{P_1}{101}=\frac{630}{273}\\ P_2 = 233 \ kPa$